0=4x^2+x-105

Solution for 0=4x^2+x-105 equation:

0=4x^2+x-105

We move all terms to the left:

0-(4x^2+x-105)=0

We add all the numbers together, and all the variables

-(4x^2+x-105)=0

We get rid of parentheses

-4x^2-x+105=0

We add all the numbers together, and all the variables

-4x^2-1x+105=0

a = -4; b = -1; c = +105;
Δ = b2-4ac
Δ = -12-4·(-4)·105
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*-4}=\frac{-40}{-8}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*-4}=\frac{42}{-8}
=-5+1/4
$